{"data":{"id":"us/27-cfr-30.64","jurisdiction":"us","citation":"27 CFR 30.64","heading":"Table 4, showing the fractional part of a gallon per pound at each percent and each tenth percent of proof of spirituous liquor.","body":"This table provides a method for use in ascertaining the wine gallon (at 60 degrees Fahrenheit) and/or proof gallon contents of containers of spirits by multiplying the net weight of the spirits by the fractional part of a gallon per pound shown in the table for spirits of the same proof. Fractional gallons beyond the first decimal will be dropped if less than 0.05 or will be added as 0.1 if 0.05 or more.\nExample.\nIt is desired to ascertain the wine gallons and proof gallons of a tank of 190 proof spirits weighing 81,000 pounds.\n81,000 × 0.14718 = 11,921.58 = 11,921.6 wine gallons.\n81,000 × 0.27964 = 22,650.84 = 22,650.8 proof gallons.\nThis table may also be used for ascertaining the quantity of water required to reduce to a given proof. To do this, divide the proof gallons of spirits to be reduced by the fractional part of a proof gallon per pound of spirits at the proof to which the spirits are to be reduced, and subtract from the quotient the net weight of the spirits before reduction. The remainder will be the pounds of water needed to reduce the spirits to the desired proof.\nExample.\nIt is desired to ascertain the quantity of water needed to reduce 1,000 pounds of 200 proof spirits, 302.58 proof gallons, to 190 proof:\n302.58 divided by 0.27964 equals 1,082.03 pounds, weight of spirits after reduction.\n1.082.03 minus 1,000 equals 82.03 pounds, weight of water required to reduce to desired proof.\nThe slight variation between this table and Tables 2, 3, and 5 on some calculations is due to the dropping or adding of fractions beyond the first decimal in those tables. This table may also be used to determine the wine gallons (at 60 degrees Fahrenheit) of distilled spirits containing dissolved solids from the total weight of the liquid and its apparent proof (hydrometer indication, corrected to 60 degrees Fahrenheit). The proof gallons may then be found by multiplying the wine gallons by the true proof.\nExample.\n5,350 pounds of blended whisky containing added solids\nTemperature °F 75.0° Hydrometer reading 92.0° Apparent proof 85.5° Obscuration 0.5° True proof 86.0°\n5,350.0 lbs. × 0.12676 (W.G. per pound factor for apparent proof of 85.5°) = 678.2 wine gallons\n678.2 W.G. × 0.86 = 583.3 proof gallons","path":["Title 27—Alcohol, Tobacco Products and Firearms","CHAPTER I—ALCOHOL AND TOBACCO TAX AND TRADE BUREAU, DEPARTMENT OF THE TREASURY","SUBCHAPTER A—ALCOHOL","PART 30—GAUGING MANUAL","Subpart E—Prescribed Tables"],"source_url":"https://www.ecfr.gov/api/versioner/v1/full/2026-08-25/title-27.xml","current_through":"2026-08-25","vintage":"","retrieved_at":"2026-08-27T02:25:11Z","sha256":"2941a768e62a3bdc67fb58d76702dc6e14dd736c5623c8a8f90ad4adf2072620","source_id":"us-cfr","stale":true,"prev":"us/27-cfr-30.63","next":"us/27-cfr-30.65"},"notice":"GroundRules: Original legal text. Not legal advice."}